Potential energy (z) assumed to be constant..
Kinetic energy changes (1 to 2) assumed to be very small
Heater
w = 0 therefore
q = h2-h1
Turbine ..(Assumed Adiabetic Expansion)..The steady flow equation as applied to a turbine..
Potential energy (z) assumed to be constant..
Kinetic energy changes (1 to 2) assumed to be very small
Turbine
q = 0 therefore
w = h2-h1
Throttling ..(Assumed Adiabetic )...The steady flow equation as applied to a orifice..
Potential energy (z) assumed to be constant..
The higher velocity at orifice section is dissipated in tube downstream of the orifice and therefore the kinetic energies at 1 and 2 are similar
Orifice
q = w = 0 therefore
therefore h1 = h2
Nozzle..(Assumed Adiabetic )...The steady flow equation as applied to smooth nozzle..
Potential energy (z) assumed to be constant..
Kinetic energy changes are assumed to be significant
Nozzle
q = w = 0 therefore
(v22 - v12 ) /2 = (h1 - h2 )
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